Find the product of (4x − 3)(2x2 − 7x + 1)
(4x − 3)(2x2 − 7x + 1)
= 8x^3 - 28x^2 + 4x - 6x^2 + 21x - 3
= 8x^3 - 34x^2 + 25x - 3
The product of (4x − 3) and (2x2 − 7x + 1) is 8x3 − 34x2 + 25x − 3.
To find the product of (4x − 3)(2x2 − 7x + 1), we will use the distributive property.
First, we multiply each term in the first expression (4x − 3) by each term in the second expression (2x2 − 7x + 1):
4x * 2x2 = 8x^3
4x * (-7x) = -28x^2
4x * 1 = 4x
-3 * 2x2 = -6x^2
-3 * (-7x) = 21x
-3 * 1 = -3
Next, we combine like terms:
8x^3 - 28x^2 + 4x - 6x^2 + 21x - 3
Now, we simplify:
8x^3 - 34x^2 + 25x - 3
Therefore, the product of (4x − 3)(2x2 − 7x + 1) is 8x^3 - 34x^2 + 25x - 3.