Jar A contains 4 green balls and 6 red balls. Jar B contains 12 green balls and 8 red balls. If a ball is drawn from each jar, what is P(red and red)?
The probability of drawing a red ball from Jar A is 6/10 or 3/5. The probability of drawing a red ball from Jar B is 8/20 or 2/5. To find the probability of both events happening (drawing red from both jars), you multiply the probabilities together:
P(red and red) = (3/5) x (2/5) = 6/25 or 0.24
Therefore, the probability of drawing a red ball from both jars is 6/25 or 0.24.
To find the probability of drawing a red ball from each jar, we multiply the individual probabilities.
P(red and red) = P(red from Jar A) x P(red from Jar B)
P(red from Jar A) = Number of red balls in Jar A / Total number of balls in Jar A
P(red from Jar A) = 6 / (4 + 6) = 6/10 = 3/5
P(red from Jar B) = Number of red balls in Jar B / Total number of balls in Jar B
P(red from Jar B) = 8 / (12 + 8) = 8/20 = 2/5
Therefore, P(red and red) = (3/5) x (2/5) = 6/25