Mary has 4/7 as many stickers as Sandy and 2/5 as many stickers as Sandy. What fraction of Cindy's stickers is Sandy's stickers?
Since Mary has 4/7 as many stickers as Sandy, and also 2/5 as many stickers, we know that:
4/7 x (Sandy's stickers) = (Mary's stickers)
2/5 x (Sandy's stickers) = (Mary's stickers)
We can set these two expressions equal to each other and solve for Sandy's stickers:
4/7 x (Sandy's stickers) = 2/5 x (Sandy's stickers)
Multiplying both sides by the least common multiple of 7 and 5 (35) gives:
20/35 x (Sandy's stickers) = 14/35 x (Sandy's stickers)
Simplifying gives:
6/35 x (Sandy's stickers) = 0
So Sandy must have 0 stickers! But this doesn't make sense, so let's try another approach.
We can use the fact that Mary has both 4/7 and 2/5 as many stickers as Sandy to set up a proportion:
4/7 x (Sandy's stickers) = 2/5 x (Sandy's stickers)
Multiplying both sides by the least common multiple of 7 and 5 (35) gives:
20 x (Sandy's stickers) = 14 x (Sandy's stickers)
Subtracting 14 x (Sandy's stickers) from both sides gives:
6 x (Sandy's stickers) = 0
So once again, we get Sandy has 0 stickers, which doesn't make sense.
It's possible that there's an error in the problem statement, or we are missing some information. Therefore, we cannot accurately determine the fraction of Cindy's stickers that Sandy has.
I expect that the question should have read
Mary has 4/7 as many stickers as Sandy and 2/5 as many stickers as Cindy.
so, 4/7 s = 2/5 c
s/c = 2/5 * 7/4 = 14/20
So Sandy has 7/10 as many stickers as Cindy
Ah, that makes sense! With that correction, the solution is as follows:
If Mary has 4/7 as many stickers as Sandy and 2/5 as many stickers as Cindy, we can set up the following two equations:
4/7 x (Sandy's stickers) = (Mary's stickers)
2/5 x (Cindy's stickers) = (Mary's stickers)
To find the ratio of Sandy's stickers to Cindy's stickers, we can set the expressions for Mary's stickers equal to each other and solve for Sandy's stickers:
4/7 x (Sandy's stickers) = 2/5 x (Cindy's stickers)
Multiplying both sides by the least common multiple of 7 and 5 (35) gives:
20 x (Sandy's stickers) = 28 x (Cindy's stickers)
Dividing both sides by 20 gives:
Sandy's stickers = 14/20 x (Cindy's stickers)
Simplifying gives:
Sandy's stickers = 7/10 x (Cindy's stickers)
Therefore, Sandy has 7/10 as many stickers as Cindy.
Let's find out how much stickers Mary has based on the given information.
Given that Mary has 4/7 as many stickers as Sandy and 2/5 as many stickers as Sandy.
Let's represent the number of stickers Sandy has as "x".
Mary has 4/7 * x stickers.
Mary also has 2/5 * x stickers.
To find the fraction of Cindy's stickers that Sandy has, we need to compare the number of stickers Sandy has to the number of stickers Cindy has.
Let's represent the number of stickers Cindy has as "y".
So, the fraction of Cindy's stickers that Sandy has is x/y.
Unfortunately, we don't have enough information to determine the values of x and y or calculate the fraction x/y.
To find the fraction of Cindy's stickers that Sandy has, we first need to determine the number of stickers each person has. Let's start by assigning a variable to Sandy's number of stickers.
Let x be the number of stickers Sandy has.
According to the given information, Mary has 4/7 as many stickers as Sandy. Therefore, Mary has (4/7)x stickers.
Additionally, we know that Mary has 2/5 as many stickers as Sandy. So, Mary has (2/5)x stickers.
To find the fraction of Cindy's stickers that Sandy has, we'll compare Sandy's stickers to Cindy's stickers. However, we need to determine the number of stickers Cindy has.
Since Mary has 4/7 as many stickers as Sandy, Cindy must have 7/4 times as many stickers as Mary. So, Cindy has (7/4) * (4/7)x stickers, which simplifies to x stickers.
Now that we know both Cindy and Sandy have x stickers, we can conclude that the fraction of Cindy's stickers that Sandy has is:
Sandy's stickers / Cindy's stickers = x / x = 1
Therefore, Sandy has the same number of stickers as Cindy, and the fraction of Cindy's stickers that Sandy has is 1 whole, which can be represented as the fraction 1/1.