Find the 10th term from the sequence 7,10,13...130
The sequence has a common difference of 3, so we can find the $n$th term using the formula $a_n = a_1 + (n-1)d$, where $a_1=7$ and $d=3$. Plugging in $n=10$, we get:
$a_{10} = 7 + (10-1)3 = 7 + 27 = \boxed{34}$
To find the 10th term of the given sequence, we need to determine the pattern of the sequence and then calculate the 10th term based on that pattern.
Looking at the given sequence: 7, 10, 13..., we can observe that each term is obtained by adding 3 to the previous term.
Let's calculate the 10th term step-by-step:
First term (n=1): 7 + (1-1) * 3 = 7
Second term (n=2): 7 + (2-1) * 3 = 10
Third term (n=3): 7 + (3-1) * 3 = 13
...
Tenth term (n=10): 7 + (10-1) * 3 = 7 + 9 * 3 = 7 + 27 = 34
Therefore, the 10th term of the sequence 7, 10, 13... is 34.