What is the probability of rolling an odd number on the first roll of a six-sided cube and rolling an even number on the second roll?(1 point)
Responses
2
2
12
, Start Fraction 1 over 2 End Fraction
14
Start Fraction 1 over 4 End Fraction
1
1
The correct response is 14, Start Fraction 1 over 4 End Fraction.
To roll an odd number on the first roll, there are 3 possible outcomes out of 6 (1, 3, 5). The probability of this happening is 3/6 or 1/2.
To roll an even number on the second roll, there are 3 possible outcomes out of 6 (2, 4, 6). The probability of this happening is also 3/6 or 1/2.
The probability of both events occurring together is found by multiplying the two probabilities:
1/2 * 1/2 = 1/4
This can be written as Start Fraction 1 over 4 End Fraction.
To find the probability of rolling an odd number on the first roll of a six-sided cube and rolling an even number on the second roll, you need to multiply the probabilities of each event happening.
Step 1: Determine the probability of rolling an odd number on the first roll. Out of the six possible outcomes (numbers 1 to 6), three of them are odd (1, 3, and 5). So the probability of rolling an odd number on the first roll is 3/6 or 1/2.
Step 2: Determine the probability of rolling an even number on the second roll. Since we already rolled the cube once, we have five possible outcomes left (the number that was not rolled on the first roll, plus the remaining even numbers). Out of these five possible outcomes, three of them are even (2, 4, and 6). So the probability of rolling an even number on the second roll is 3/5.
Step 3: Multiply the probabilities from steps 1 and 2 to get the overall probability. This is done by multiplying the numerators together (1 * 3) and multiplying the denominators together (2 * 5). The result is 3/10.
Therefore, the probability of rolling an odd number on the first roll of a six-sided cube and rolling an even number on the second roll is 3/10.