You have received a patient who has stung by waps which produce an alkaline toxic whose concentration is estimated at 3M(mole per cubic decimeter ).unfortunately there is no acid substance in the pharmacy with the same concetration as the toxic produced by wasps that can be given to the patient in order to directly neutralize the base .However the lab has a bottle of aqueous hydrochloric acid whose concentration is 98% .Describe with appropriate calculation how you could prepare a 3M(3mole per cubic decimeter) solution with a volume of 200ml from stock solution (3MHC),so that you use on a patient to neutralize the alkaline toxic?
To prepare a 3M solution of hydrochloric acid from the stock solution of 98%, we need to dilute the stock solution appropriately. Let's assume we need a final volume of 200 ml of the 3M solution.
We can use the following formula to calculate the volume of stock solution we need to take and the volume of water we need to add:
C1V1 = C2V2
where C1 is the concentration of the stock solution (98%), V1 is the volume of stock solution we need to take, C2 is the desired concentration (3M), and V2 is the final volume of the solution (200 ml).
Rearranging the formula, we get:
V1 = (C2V2)/C1
Substituting the values, we get:
V1 = (3 x 200)/0.98
V1 = 612.24 ml
This means we need to take 612.24 ml of the stock solution and add water to make a final volume of 200 ml. We can calculate the volume of water needed as:
Volume of water = V2 - V1
= 200 - 612.24
= -412.24 ml
This negative value means we need to subtract 412.24 ml of the stock solution from 200 ml of water to get the final volume of 200 ml.
Therefore, to prepare a 3M solution of hydrochloric acid from the stock solution of 98%, we need to mix 612.24 ml of the stock solution with 412.24 ml of water to get a final volume of 200 ml.
This solution can be used to neutralize the alkaline toxic produced by the wasp sting.
To prepare a 3M (3 mole per cubic decimeter) solution of hydrochloric acid (HCl) with a volume of 200ml from a stock solution of 3M HCl, you can perform the following steps:
1. Determine the amount of the stock solution required: The desired volume of the final solution is 200ml, which is equivalent to 0.2 liters. We can use the formula:
Volume (V1) x Molarity (M1) = Volume (V2) x Molarity (M2)
where V1 is the volume of the stock solution, M1 is the molarity of the stock solution, V2 is the desired volume, and M2 is the desired molarity.
Rearranging the formula, we get:
V1 = (V2 x M2) / M1
Substituting the values:
V1 = (0.2 x 3) / 3
V1 = 0.2 liters
So you would need 0.2 liters (200 ml) of the stock solution.
2. Calculate the dilution factor: The concentration of the stock solution is 3M, and you want to prepare a 3M solution. Since the desired concentration is the same as the stock concentration, the dilution factor would be:
Dilution factor = V1 / V2
where V1 is the volume of the stock solution and V2 is the volume of the final solution.
Substituting the values:
Dilution factor = 0.2 / 0.2
Dilution factor = 1
Since the dilution factor is 1, it means that no dilution is required. The stock solution can be used directly without any further dilution.
3. Calculate the volume of the stock solution required: Since the dilution factor is 1, the volume of the stock solution required would be equal to the desired volume of the final solution, which is 200ml.
Therefore, you can use 200ml of the stock solution of 3M hydrochloric acid for neutralizing the alkaline toxin.