What is the value of 12x^-3y^1 for x=-1 and y=5?
Substitute the values of x and y into the equation:
12x^-3y^1
= 12(-1)^-3(5)^1
= 12(-1/1)(5)
= -60
Therefore, the value of 12x^-3y^1 for x=-1 and y=5 is -60.
To find the value of 12x^-3y^1 for x=-1 and y=5, we substitute the values of x and y into the expression.
Step 1: Substitute the value of x into the expression.
12(-1)^-3y^1
Step 2: Evaluate the value of x.
(-1)^-3 = -1 : The negative exponent negates the base.
Step 3: Substitute the value of y into the expression.
12(-1)y^1
Step 4: Evaluate the value of y.
y^1 = 5 : Any value raised to the power of 1 remains the same.
Step 5: Simplify the expression.
12(-1)(5)
Step 6: Perform the multiplication operation.
-60
Therefore, the value of 12x^-3y^1 for x=-1 and y=5 is -60.