What is the volume of the cone rounded to the nearest tenth?
The height of the cone is 19 yd.
Radius: 7 yd.
2646.3
1462.4
1039.0
975.0
The volume of the cone is V = (1/3)πr^2h, where r is the radius and h is the height.
Substituting the given values, we get:
V = (1/3)π(7 yd)^2(19 yd)
V ≈ 1462.4 yd^3
Rounding to the nearest tenth, we get:
V ≈ 1462.4 (rounded to the nearest tenth)
V ≈ 1462.4
Therefore, the volume of the cone rounded to the nearest tenth is 1462.4. The answer is B.
To find the volume of a cone, you can use the formula V = (1/3) * π * r^2 * h. Where V is the volume, π is a mathematical constant approximately equal to 3.14159, r is the radius of the cone, and h is the height of the cone.
Plugging in the given values:
V = (1/3) * 3.14159 * (7)^2 * 19
Calculating this:
V = (1/3) * 3.14159 * 49 * 19
V ≈ 1039.0
Therefore, the volume of the cone, rounded to the nearest tenth, is 1039.0. So the answer to your question is option C: 1039.0.