Over the past 6 seasons, one baseball player's batting averages were 0.2210.316, 0.3260.296, 0.267 and 0 A second player's batting averages were 0.275.0.3110.286, 0262, and 0.184 What are the range and mean of each player's batting averages? Use your results to compare the players Find the range and mean of the first player's batting averages The range Type an integer or a Round to the nearest thousandth as needed ) The mean is
0.326 - 0.221 = 0.105 (rounded to the nearest thousandth)
Mean = (0.221 + 0.316 + 0.326 + 0.296 + 0.267 + 0)/6 = 0.258 (rounded to the nearest thousandth)
Find the range and mean of the second player's batting averages
The range = 0.286 - 0.184 = 0.102 (rounded to the nearest thousandth)
Mean = (0.275 + 0.311 + 0.286 + 0.262 + 0.184)/5 = 0.2636 (rounded to the nearest thousandth)
Comparing the two players, the first player has a smaller range, but a lower mean. The second player has a larger range, but a higher mean. This suggests that the first player is more consistent, but the second player has higher potential for a good performance.
To find the range and mean of the first player's batting averages, we need to calculate the difference between the highest and lowest averages for the range, and the average of all the averages for the mean.
The first player's batting averages are:
0.221, 0.316, 0.326, 0.296, 0.267, and 0.
To find the range:
Arrange the averages in ascending order:
0, 0.221, 0.267, 0.296, 0.316, 0.326.
The highest average is 0.326 and the lowest is 0, so the range is:
0.326 - 0 = 0.326.
To find the mean:
Add all the averages and divide by the total number of averages:
0 + 0.221 + 0.267 + 0.296 + 0.316 + 0.326 = 1.426.
Divide 1.426 by 6 (the number of averages):
1.426 / 6 = 0.2377 (rounded to the nearest thousandth).
Therefore, the range of the first player's batting averages is 0.326, and the mean is 0.238.