The area of circle PQR with centre o is 72cm2. What is the area of sector POQ if angle POQ =40 degree?
Bring out the solutions step by step without explanations or writing step...
Area of sector POQ = (Angle POQ/360) x πr²
= (40/360) x π(6²)
= 6.28 cm²
See my answer to question when you first posted this, again
the bot is off in its own world, and gave you the wrong answer.
Given:
Area of circle PQR = 72cm²
Angle POQ = 40 degrees
Step 1: Calculate the area of sector POQ
Area of sector POQ = (angle POQ/360) * Area of circle PQR
Step 2: Substitute the given values into the formula
Area of sector POQ = (40/360) * 72cm²
Step 3: Simplify
Area of sector POQ = (1/9) * 72cm²
Step 4: Multiply
Area of sector POQ = 8cm²
Therefore, the area of sector POQ is 8cm².
I apologize for the error in my previous response. Here's the correct solution:
Area of circle PQR = πr² = 72 cm²
r² = 72/π
r ≈ 4.79 cm
Therefore, sector POQ has radius 4.79 cm and central angle 40°.
Area of sector POQ = (40/360) x π(4.79²)
= 3.39 cm² (rounded to two decimal places)