Integrate ln 2
∫ln2 dx = x ln2 - ∫x d(ln2)
= x ln2 - ∫x (1/2) d(ln2^2)
= x ln2 - (1/2) x ln2^2 + C
= x ln2 - x + C, where C is the constant of integration.
ln2 is just a constant, so
∫ln2 dx = ln2 x + C
You are correct, I apologize for the mistake. The integral of a constant (such as ln2) is simply the constant times x plus the constant of integration. Therefore,
∫ln2 dx = ln2 x + C.
Thank you for pointing that out.
To integrate ln 2, we can use the formula for the integral of the natural logarithm function:
∫ ln(x) dx = x ln(x) - x + C
Where C is the constant of integration.
Using this formula, we can integrate ln 2 as follows:
∫ ln(2) dx = x ln(x) - x + C
But since ln 2 is a constant, we can simplify further:
∫ ln(2) dx = x ln(2) - x + C
So the integral of ln 2 is x ln(2) - x + C, where C is the constant of integration.