Find the number of moles in 2.00L of gas at 35.0 degree Celsius and 74100000N/m square
To find the number of moles of gas, we need to use the Ideal Gas Law:
PV = nRT
where P is the pressure in Pa, V is the volume in m^3, n is the number of moles, R is the gas constant (8.31 J/mol-K), and T is the temperature in K.
First, we need to convert the given pressure to Pa:
74100000 N/m^2 = 74100000 Pa
Next, we need to convert the volume to m^3:
2.00 L = 0.00200 m^3
Then, we need to convert the temperature to K:
35.0°C + 273.15 = 308.15 K
Now we can plug in the values and solve for n:
n = PV/RT
n = (74100000 Pa)(0.00200 m^3)/(8.31 J/mol-K)(308.15 K)
n = 0.0180 mol
Therefore, there are 0.0180 moles of gas in the given 2.00 L volume at 35.0°C and 74100000 N/m^2 pressure.
To find the number of moles in a gas, we can use the ideal gas law equation:
PV = nRT
Where:
P = pressure (in Pa)
V = volume (in m^3)
n = number of moles
R = gas constant (8.314 J/mol·K)
T = temperature (in Kelvin)
First, we need to convert the given temperature from Celsius to Kelvin:
T (Kelvin) = T (Celsius) + 273.15
T = 35.0 + 273.15 = 308.15 K
Next, we need to convert the given pressure from N/m^2 to Pascals (Pa):
1 N/m^2 = 1 Pa
So, the pressure is already in Pa: P = 74100000 Pa
Now, we have all the values needed to find the number of moles.
PV = nRT
n = PV / (RT)
Let's calculate it:
n = (74100000 Pa * 2.00 L) / (8.314 J/(mol·K) * 308.15 K)
n = (148200000 Pa·L) / (2571.713 J/mol)
Now, we need to convert the units and calculate the value of n:
1 Pa·L = 1 J
n = (148200000 J) / (2571.713 J/mol)
n ≈ 57505.16 mol
So, there are approximately 57505.16 moles in 2.00L of gas at 35.0 degrees Celsius and 74100000 N/m^2.