Which combination of charge and distance would lead to the strongest repulsive force ? a + 1 charge and a -1 charge at a distance of 1.5 meters a + 3 charge and a + 3 charge at a distance of 0.5 meters a + 4 charge and a - 4 charge at a distance of 0.5 meters a + 2 charge and a + 2 charge at a distance of 1.5 meters
Which combination of charge and distance would lead to the strongest repulsive force ?
a + 1 charge and a -1 charge at a distance of 1.5 meters
a + 3 charge and a + 3 charge at a distance of 0.5 meters
a + 4 charge and a - 4 charge at a distance of 0.5 meters
a + 2 charge and a + 2 charge at a distance of 1.5 meters
The strongest repulsive force would be between a +4 charge and a -4 charge at a distance of 0.5 meters. This is because the magnitude of the charges (4) is greater than any other combination, and the distance is smaller, leading to a stronger force according to Coulomb's law.
You're wrong, that would be the strongest attractive force
You are correct, I apologize for my mistake. The strongest repulsive force would be between a +3 charge and a +3 charge at a distance of 0.5 meters because the magnitude of the charges (3) is higher than any other combination given, and the distance is smaller than the other options. According to Coulomb's law, the strength of the repulsive force decreases as the distance between the charges increases.
An electromagnet can be made by wrapping coils of wire around a nail and running a current through the wire. How can the strength of the electromagnet be maximized ? (1 point ) The thickness of the nail and number of coils around the nail should be maximized .
The length and thickness of the nail should be maximized
. The current and length of the nail should be maximized .
The current and number of coils around the nail should be maximized .
To determine which combination of charge and distance would lead to the strongest repulsive force, we need to calculate the values of the forces using Coulomb's Law.
Coulomb's Law states that the force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.
Let's calculate the forces for each combination:
1. Combination 1: +1 charge and -1 charge at a distance of 1.5 meters
Force = (k * q1 * q2) / r^2
= (9.0 x 10^9 Nm^2/C^2 * +1C * -1C) / (1.5m)^2
= -6.0 x 10^9 N
2. Combination 2: +3 charge and +3 charge at a distance of 0.5 meters
Force = (k * q1 * q2) / r^2
= (9.0 x 10^9 Nm^2/C^2 * +3C * +3C) / (0.5m)^2
= 9.0 x 10^10 N
3. Combination 3: +4 charge and -4 charge at a distance of 0.5 meters
Force = (k * q1 * q2) / r^2
= (9.0 x 10^9 Nm^2/C^2 * +4C * -4C) / (0.5m)^2
= -1.44 x 10^12 N
4. Combination 4: +2 charge and +2 charge at a distance of 1.5 meters
Force = (k * q1 * q2) / r^2
= (9.0 x 10^9 Nm^2/C^2 * +2C * +2C) / (1.5m)^2
= 0.64 x 10^10 N
From the calculations above, we can see that the combination with the strongest repulsive force is Combination 3: +4 charge and -4 charge at a distance of 0.5 meters, with a force of -1.44 x 10^12 Newtons.
To determine which combination of charge and distance would lead to the strongest repulsive force, we need to calculate the magnitude of the repulsive force for each combination using Coulomb's Law.
Coulomb's law states that the magnitude of the electrostatic force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. Mathematically, it can be expressed as:
F = k * (|q1| * |q2|) / r^2
Where:
F is the magnitude of the electrostatic force,
k is the electrostatic constant (k ≈ 9 × 10^9 N m^2/C^2),
|q1| and |q2| are the magnitudes of the charges, and
r is the distance between the charges.
Let's calculate the magnitude of the repulsive force for each combination and compare the results:
1. Combination: +1 charge and -1 charge at a distance of 1.5 meters
F = k * (|+1| * |-1|) / (1.5)^2
= k / 2.25
2. Combination: +3 charge and +3 charge at a distance of 0.5 meters
F = k * (|+3| * |+3|) / (0.5)^2
= 9k / 0.25
3. Combination: +4 charge and -4 charge at a distance of 0.5 meters
F = k * (|+4| * |-4|) / (0.5)^2
= 16k / 0.25
4. Combination: +2 charge and +2 charge at a distance of 1.5 meters
F = k * (|+2| * |+2|) / (1.5)^2
= 4k / 2.25
Comparing the calculations, we can see that the combination with the strongest repulsive force is:
Combination: +4 charge and -4 charge at a distance of 0.5 meters
This is because the magnitude of the force is proportional to the product of the charges, and in this combination, the charges have the highest magnitude. Additionally, the force is inversely proportional to the square of the distance, so a smaller distance leads to a stronger force. In this combination, the distance is the smallest among the given options, further contributing to the strongest repulsive force.