A bird drops a stick to the ground from a height of 60 ft. The function h=-16t+60 gives the stick's approximate height h above the ground, in feet, after t seconds. At about what time does the stick hit the ground?
To find the time when the stick hits the ground, we need to find when h = 0. So we set the equation -16t + 60 = 0 and solve for t:
-16t + 60 = 0
-16t = -60
t = 3.75
Therefore, the stick hits the ground after approximately 3.75 seconds.
ah, where did you get h=-16t+60 ??????????????
That is a constant downward speed of 16 m/s
More probably you mean a constant downward acceleration of g, about 32 m/s^2 (of gravity)
that would be
h = 60 - (1/2) 32 t^2
h= 60 - 16 t^2 (NOT t)
if h = 0
t = sqrt (60/16)
t = 1.94 seconds
You are correct, I apologize for my mistake. The correct function should be h = -16t^2 + 60, which represents the height h of the stick above the ground as a function of time t, taking into account the acceleration due to gravity. Setting h to 0 and solving for t, we get:
0 = -16t^2 + 60
16t^2 = 60
t^2 = 60/16
t = sqrt(60/16)
t ≈ 1.94 seconds
Therefore, the stick hits the ground approximately 1.94 seconds after being dropped. Thank you for correcting my error!
Not your fault really. The student typed it wrong.
Understood, thank you again for catching the mistake! As an AI language model, I rely on input from the user and I appreciate any feedback or corrections to ensure that the information provided is accurate.
To determine at what time the stick hits the ground, we need to find the value of t when the height (h) is equal to 0.
Given the function h = -16t + 60, we substitute h with 0 and solve for t:
0 = -16t + 60
Rearranging the equation:
16t = 60
Next, we divide both sides of the equation by 16:
t = 60/16
Simplifying:
t ≈ 3.75 seconds
Therefore, the stick hits the ground at approximately 3.75 seconds.
To find the time when the stick hits the ground, we need to determine when the height (h) of the stick becomes 0.
Given that the function h = -16t + 60 represents the stick's approximate height above the ground after t seconds, we can set this equation equal to 0 and solve for t.
-16t + 60 = 0
To solve for t, we'll isolate the t-term by subtracting 60 from both sides:
-16t = -60
Next, we'll divide both sides of the equation by -16 to solve for t:
t = -60 / -16
Simplifying, we get:
t = 3.75
Therefore, the stick hits the ground at approximately 3.75 seconds.