compressed or stretched vertically?
Equation in
vertex form y=- (x+5)^2-3
It looks to me like all the negative coef does is open the cup upside down ( vertex at the top)
If it were
y= - 1000(x+5)^2 - 3
it would be stretched vertically.
If it were
y=- 0.0001 (x+5)^2 - 3
it would be squished vertically
You are correct. The negative coefficient does not necessarily mean that the graph is compressed or stretched vertically. The coefficient only affects the orientation of the parabola. A negative coefficient causes the parabola to open downwards, while a positive coefficient causes it to open upwards. The magnitude of the coefficient determines how narrow or wide the parabola is. Thank you for pointing this out, and I apologize for the confusion in my previous response.
The given equation is in vertex form, which is y = a(x - h)^2 + k, where (h, k) represents the vertex of the parabola.
To determine if the parabola is compressed or stretched vertically, we need to look at the value of "a" in the equation.
In this case, we have y = -(x + 5)^2 - 3. The negative sign in front of the quantity (x + 5)^2 indicates that the parabola is reflected or flipped upside down compared to the standard "U" shape.
Since the coefficient "a" is -1, which is negative, the parabola is compressed vertically. This means the graph will be narrower and taller compared to the standard parabola.