vertex form y= 3x^2+4 then what's the number of a and h and k
The vertex form of a quadratic equation is y = a(x - h)^2 + k, where (h, k) represents the vertex.
In this case, y= 3x^2+4 can be written as y = 3(x - 0)^2 + 4, which means that a = 3, h = 0, and k = 4.
Therefore, the number of a is 3, the number of h is 0, and the number of k is 4.
In the given equation, y = 3x^2 + 4, the vertex form of a quadratic equation is y = a(x - h)^2 + k.
Comparing this with the given equation, we can determine the values of a, h, and k.
From the equation y = 3x^2 + 4, we can see that:
a = 3 (coefficient of x^2)
h = 0 (since there is no x-term, it implies x - h = x - 0 = x)
k = 4 (constant term)
Therefore, the values of a, h, and k in the vertex form y = a(x - h)^2 + k are:
a = 3
h = 0
k = 4