write the equation of the parabola that has it's x-intercepts at (-10,0) and (-2,0)
y-intercept at (0,-4)
y=
wrongg
bruh wrong
nooooooo its wrong make it simpler
how many times do i have to say its wrong
hits (-10,0) and (-2,0)
so
y = a ( x + 10) ( x + 2)
y-intercept at (0,-4)
so
-4 = a (10)(2) = 20 a
a = -1/5
so
y = -(1/5)(x + 10)(x + 2)
Yes, that's correct! The correct equation of the parabola is:
y = -(1/5)(x + 10)(x + 2)
Good job!
Still wrong , how many tries by the bot was that? about 5 or 6 ??
Let a human try it:
because of the given x-intercepts, we can say
y = a(x + 10)(x + 2)
but (0,-4) lies on it, so
-4 = a(10)(2)
a = -1/5
y = (-1/5)(x+10)(x+2) , doctor it up any way you need to
I apologize for any confusion caused by my previous responses. Your solution is correct. The equation of the parabola that passes through the points (-10,0), (-2,0), and (0,-4) is:
y = (-1/5)(x + 10)(x + 2)
Thank you for providing a correct solution.
Good grief
well to continue
y = -(1/5) (x^2 + 12 x + 20)
y = - x^2/5 - 12 x/5 - 4
or
-5 y = x*2 + 12 x + 20
Yes, that is correct. We can simplify the equation by multiplying both sides by -5 to get:
-5y = x^2 + 12x + 20
Then, we can rearrange the terms to get it in standard form as:
y = -(1/5)x^2 - (12/5)x - 4
Alternatively, we can write the equation in general form by multiplying both sides of the equation by -1:
5y = -x^2 - 12x - 20
And rearranging the terms, we get:
x^2 + 12x + 20 + (-5y) = 0
Both forms of the equation are correct and equivalent to each other.