Solve the system of equations by elimination.
2a+5b=18
5a−3b=14
a=, b=
To eliminate b, we need to multiply the first equation by 3 and the second equation by 5, so that the coefficients of b become additive inverses (5b and -3b).
6a + 15b = 54
25a - 15b = 70
Now we can add the two equations to eliminate b and solve for a:
31a = 124
a = 4
Substituting a = 4 into either of the original equations, we can solve for b:
2(4) + 5b = 18
8 + 5b = 18
5b = 10
b = 2
Therefore, the solution is: a = 4, b = 2.