Write in the correct coefficients for the balanced equation:
__CH4 + __O2 → __CO2 + __H2O
1CH4 + 2O2 → 1CO2 + 2H2O
what is the chemical reaction for
C4H8 + O2 → 4CO2 + 4H2O
decomposition
synthesis
combustion
double displacement
single displacement
The chemical reaction
C4H8 + O2 → 4CO2 + 4H2O
is an example of combustion.
If x= root 5- root 3 upon root 5+root 3, evaluate x+y=
To evaluate the value of x, we use the conjugate of the denominator which is (root 5 - root 3)
So x = (root 5 - root 3) / (root 5 + root 3) * (root 5 - root 3) / (root 5 - root 3)
x = ((root 5)^2 - (root 3)^2) / ((root 5)^2 - (root 3)^2)
x = (5 - 3) / (5 - 3)
x = 2
We are not given any value for y, so we cannot determine its value.
And y's value was root 5 + root 3 upon root 5- root 3 now calculate the question
Now that we have the value of x (which is 2) and the value of y (which is (root 5 + root 3) / (root 5 - root 3)), we can evaluate the expression x+y as follows:
x + y = 2 + ((root 5 + root 3) / (root 5 - root 3))
To simplify this expression, we can rationalize the denominator as follows:
x + y = 2 + ((root 5 + root 3) / (root 5 - root 3)) * ((root 5 + root 3) / (root 5 + root 3))
x + y = 2 + ((5 + 2root 15 + 3) / (5 - 3))
x + y = 2 + (8 + 2root 15)
Therefore, x + y = 10 + 2root 15.
If x= root 5 - root 3 upon root 5 + root 3 and y= root 5 + root3 upon root 5- root 3, evaluate x+y
To solve this problem, we need to rationalize the denominators of x and y so that we can add them together.
Starting with x:
x = (root 5 - root 3) / (root 5 + root 3)
x = [(root 5 - root 3) / (root 5 + root 3)] * [(root 5 - root 3) / (root 5 - root 3)]
x = (5 - 3 - 2root 15) / (5 - 3)
x = -1 + root 15
Next, let's simplify y in the same way:
y = (root 5 + root 3) / (root 5 - root 3)
y = [(root 5 + root 3) / (root 5 - root 3)] * [(root 5 + root 3) / (root 5 + root 3)]
y = (5 + 3 + 2root 15) / (5 - 3)
y = 4 + 2root 15
Now we can add x and y together:
x + y = (-1 + root 15) + (4 + 2root 15)
x + y = 3 + 3root 15
Therefore, the value of x+y is 3 + 3root 15.
To balance the equation __CH4 + __O2 → __CO2 + __H2O, we need to determine the correct coefficients for each molecule to ensure that the number of atoms on both sides of the equation are the same.
First, let's start by counting the number of each type of atom on both sides of the equation:
On the left side (reactants):
- Carbon (C): There is 1 carbon atom in CH4.
- Hydrogen (H): There are 4 hydrogen atoms in CH4.
- Oxygen (O): There are 2 oxygen atoms in O2.
On the right side (products):
- Carbon (C): There is 1 carbon atom in CO2.
- Hydrogen (H): There are 2 hydrogen atoms in H2O.
- Oxygen (O): There are 3 oxygen atoms in CO2 and 1 oxygen atom in H2O, totaling 4 oxygen atoms.
Now, let's balance the equation by adjusting the coefficients:
__CH4 + __O2 → __CO2 + __H2O
- Since there is 1 carbon atom on both sides of the equation, we don't need to adjust the coefficient for CH4 or CO2.
- However, there are 4 hydrogen atoms on the reactant side and only 2 hydrogen atoms on the product side. To balance the hydrogen, we should put a coefficient of 2 in front of H2O:
__CH4 + __O2 → __CO2 + 2H2O
- Lastly, there are 2 oxygen atoms on the reactant side and 4 oxygen atoms on the product side. To balance the oxygen, we need to put a coefficient of 2 in front of O2:
__CH4 + 2O2 → __CO2 + 2H2O
With the coefficients in place, the balanced equation is:
CH4 + 2O2 → CO2 + 2H2O
Now, you can substitute any whole numbers (except zero) for the underscores to specify the actual coefficients for each molecule.