You mix the letters M,A,T,H,E,M,A,T, I,C,A and L thoroughly. Without looking you draw one letter. Find the probability P(A). Write the problem as
A fraction in simplest form, a decimal, and a percent
The number of ways to choose one letter out of 11 is 11.
The number of ways to choose the letter A out of the 11 is 2 (there are two A's in the mix).
So the probability of drawing an A is:
2/11
or
0.18 (rounded to two decimal places)
or
18.18% (rounded to two decimal places)
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To find the probability of drawing the letter "A" from the given set of letters, we first need to determine the total number of letters and the number of occurrences of "A" in the set.
Total number of letters: 12 (M,A,T,H,E,M,A,T,I,C,A,L)
Number of occurrences of "A": 3
Now, we can calculate the probability.
Probability (P) = Number of favorable outcomes / Total number of possible outcomes
Number of favorable outcomes: 3 (since there are 3 occurrences of "A")
Total number of possible outcomes: 12 (total number of letters)
P(A) = 3 / 12
To express the fraction in simplest form, we can simplify it by dividing both the numerator and denominator by their greatest common divisor, which is 3.
P(A) = 1 / 4
As a decimal, this fraction is equal to 0.25.
As a percent, we can convert the decimal to a percent by multiplying by 100.
P(A) = 0.25 * 100 = 25%
Therefore, the probability of drawing the letter "A" is 1/4, 0.25, or 25%.