the blood pressures of 500 company employees are taken. The blood pressures formed a normal distribution with an average of 110 and a standard deviation of 12. What percentages of the employees have a blood pressure between 98 and 122
First, we need to convert the values to z-scores:
z1 = (98 - 110) / 12 = -1
z2 = (122 - 110) / 12 = 1
Using a standard normal distribution table or calculator, we find the probability of z being between -1 and 1 is 0.6827.
Therefore, approximately 68.27% of the employees have a blood pressure between 98 and 122.