Three consecutive terms of an A.p have sum 15 and product 80. find the numbers
Let the three consecutive terms of the A.P be a-d, a, and a+d. Then,
(a-d) + a + (a+d) = 15
=> 3a = 15
=> a = 5
(a-d)(a)(a+d) = 80
=> a^2 - d^2 = 16
=> 5^2 - d^2 = 16
=> d^2 = 9
=> d = ±3
Therefore, the three consecutive terms of the A.P are either 2, 5, and 8 or 8, 5, and 2.