What is the probability of rolling an odd number on the first try of a six- sided cube and rolling an even number on the second roll
1/4
1
1/2
2
There are three odd numbers and three even numbers on a six-sided cube. Therefore, the probability of rolling an odd number on the first try is 3/6 or 1/2. On the second roll, there are now only three numbers left, two of which are even. Therefore, the probability of rolling an even number on the second roll is 2/3. To find the probability of both events happening together (i.e. rolling an odd number on the first try and an even number on the second roll), we multiply the probabilities: (1/2) x (2/3) = 1/3. So the answer is C) 1/2.
Are you sure?
I apologize for the mistake. The correct answer is actually: (1/2) x (1/2) = 1/4. The probability of rolling an odd number on the first try is still 1/2, but the probability of rolling an even number on the second roll is also 1/2, since there are three even numbers and six total numbers left after the first roll. So the probability of both events happening together is (1/2) x (1/2) = 1/4.
Are you 100% sure?
Yes, I am 100% sure that the correct answer is (1/2) x (1/2) = 1/4. I apologize for the confusion earlier. Thank you for bringing it to my attention.
To find the probability of rolling an odd number on the first try of a six-sided cube and rolling an even number on the second roll, we need to determine the probability for each individual roll and then multiply them together.
First, let's consider the probability of rolling an odd number on the first roll. On a six-sided cube, there are three odd numbers: 1, 3, and 5. Since there are six equally likely outcomes (the numbers 1 to 6), the probability of rolling an odd number on the first roll is 3/6, which simplifies to 1/2.
Next, let's consider the probability of rolling an even number on the second roll. Since we have already rolled the cube once and obtained an outcome, there are now five remaining numbers on the cube: 1, 2, 3, 4, and 5. Out of these remaining numbers, there are three even numbers: 2, 4, and 6. Therefore, the probability of rolling an even number on the second roll is 3/5.
To find the probability of both events occurring, we need to multiply the individual probabilities together:
P(Odd on first roll) * P(Even on second roll) = 1/2 * 3/5 = 3/10
Therefore, the probability of rolling an odd number on the first try of a six-sided cube and rolling an even number on the second roll is 3/10.
So, the correct answer is 3/10, not one of the options given in the question.