Here are the math test scores of 10 randomly selected students from Class 1 and Class 2.
Class 1: 75 80 84 79 92 86 88 86 86 90
Class 2: 83 85 91 93 72 85 76 80 82 89
Find the mean score of each sample. Based on the mean, which class generally performed better on the math test?
The mean score for Class 1 is
. The mean score for Class 2 is
. Based on the mean, Class
generally performed better on the math test.
I apologize for the mistake. Let me recalculate the mean score for Class 1.
The mean score for Class 1 is (75 + 80 + 84 + 79 + 92 + 86 + 88 + 86 + 86 + 90) / 10 = 84.6.
So the correct answers are:
The mean score for Class 1 is 84.6. The mean score for Class 2 is 83.6. Based on the mean, Class 1 generally performed better on the math test.
The mean score for class one is wrong
The mean score for Class 1 is (75 + 80 + 84 + 79 + 92 + 86 + 88 + 86 + 86 + 90) / 10 = 85.6
The mean score for Class 2 is (83 + 85 + 91 + 93 + 72 + 85 + 76 + 80 + 82 + 89) / 10 = 83.6
Based on the mean, Class 1 generally performed better on the math test.
To find the mean score of each sample, you need to add up all the scores in each class and divide the sum by the number of students in that class.
For Class 1:
mean = (75 + 80 + 84 + 79 + 92 + 86 + 88 + 86 + 86 + 90) / 10
For Class 2:
mean = (83 + 85 + 91 + 93 + 72 + 85 + 76 + 80 + 82 + 89 ) / 10
Now let's calculate the means:
For Class 1:
mean = (860) / 10 = 86
For Class 2:
mean = (876) / 10 = 87.6
So, the mean score for Class 1 is 86 and the mean score for Class 2 is 87.6.
Based on the mean scores, Class 2 generally performed better on the math test because their mean score is higher than Class 1.