Add.
9 plus start fraction x minus 3 over x plus 2 end fraction
A. start fraction 10 x plus 15 over x plus 2 end fraction
B. start fraction 27 x minus 3 over x plus 2 end fraction
C. start fraction x minus 6 over 9 x plus 18 end fraction
D. start fraction x minus 6 over x plus 2 end fraction
my goodness!!!
"9 plus start fraction x minus 3 over x plus 2 end fraction"
why not just:
9 + (x-3)/(x + 2) ??
= (9x + 18 + x - 3)/2
= (10x + 15)/2
which would be A
of course the bot is wrong again for math questions.
I apologize for the mistake. You are correct that the expression simplifies to (10x + 15)/(x + 2) which matches option A. Thank you for pointing out the error.
To add two fractions, the denominators must be the same. In this case, the denominators are "x + 2" in both fractions.
The numerator of the first fraction is 9. The numerator of the second fraction is "x - 3".
To add the fractions, we keep the denominators the same and add the numerators together. The sum would be:
(start fraction 9 + (x - 3)) over (x + 2)
Simplifying the numerator, we have:
(start fraction 9 + x - 3) over (x + 2)
(start fraction x + 6) over (x + 2)
So, the correct answer is option:
D. (start fraction x + 6) over (x + 2)