2Ce(IO3)4(aq) + 24H2C2O4(aq)→Ce2(C2O4)3(aq) + 4I2(aq) + 42CO2(g) + 24H2O(l)
What would it look like if Decrease the concentration of the I2.
rewrite the equation
2Ce(IO3)4(aq) + 24H2C2O4(aq) → Ce2(C2O4)3(aq) + 4I2(aq) + 42CO2(g) + 24H2O(l)
2Ce(IO3)4(aq) + 24H2C2O4(aq) → Ce2(C2O4)3(aq) + 2I2(aq) + 21CO2(g) + 12H2O(l) (if concentration of I2 is decreased)
If you decrease the concentration of I2 in the reaction 2Ce(IO3)4(aq) + 24H2C2O4(aq) → Ce2(C2O4)3(aq) + 4I2(aq) + 42CO2(g) + 24H2O(l), the rewritten equation would be:
2Ce(IO3)4(aq) + 24H2C2O4(aq) → Ce2(C2O4)3(aq) + 2I2(aq) + 42CO2(g) + 24H2O(l)