3. A bag contains 2 red marbles and 4 green marbles. Two marbles are drawn at random. One marble is drawn and not replaced. Then a second marble is drawn. What is the probability that the first marble is green and the second one is red?
2
2/15
4/15
1/4
The probability of drawing a green marble first is 4/6 (or 2/3), since there are 4 green marbles out of a total of 6 marbles. Then, since one marble has already been drawn and not replaced, there are only 5 marbles left in the bag, with 2 red marbles. The probability of drawing a red marble second is 2/5. To find the probability of both events happening together, we multiply the probabilities:
(4/6) * (2/5) = 8/30 = 4/15
Therefore, the answer is C) 4/15.