Y=3(x-5)(x-17) what the zeros and Axis of symmetry
First, we need to simplify the equation by multiplying the two binomials:
Y=3(x-5)(x-17)
Y=3(x²-22x+85)
Y=3x²-66x+255
The axis of symmetry is given by the formula:
x= -b/2a
where a = 3 and b = -66.
x= -(-66)/2(3)
x= 11
So, the axis of symmetry is x = 11.
To find the zeros, we set Y equal to zero:
0=3x²-66x+255
We can simplify this equation by dividing everything by 3:
0=x²-22x+85
Now we need to factor the quadratic equation:
0=(x-5)(x-17)
So the zeros are x=5 and x=17.
Therefore, the zeros are x = 5 and x = 17, and the axis of symmetry is x = 11.