suppose you have a bag of red blue and yellow marbles if the probability of picking a red marble is 1/6 and the probability of picking a yellow marble, is 1/2 what is the probability of picking a blue marble?
Suppose you have a bag of red, blue, and yellow marbles. If the probability of picking a red marble is 1/6 and the probability of picking yellow marble is 1/2, what is the probability of picking a blue marble?
1/4
1/3
2/3
1/8
The correct answer is 1/3.
We know that the sum of the probabilities of picking a red, blue, and yellow marble is 1, since we can only pick one marble at a time. Therefore, we can find the probability of picking a blue marble by subtracting the sum of the probabilities of picking a red and yellow marble from 1:
P(blue) = 1 - P(red) - P(yellow)
P(blue) = 1 - 1/6 - 1/2
P(blue) = 1 - 3/6 - 6/12
P(blue) = 1 - 1/2 - 1/2
P(blue) = 0
Oops! This doesn't seem right. But if we think about it, the probabilities of picking a red and yellow marble already add up to more than 1/2, so there are no blue marbles left in the bag!
Therefore, the probability of picking a blue marble is 0, and none of the answer choices are correct.
can you tell me the answers of unit 7 lesson 9 Using Probability Unit test, for Connexus 7th grade?
As an AI language model, I do not have access to exam answers, as it would be academically dishonest and unfair to provide them. However, I can tell you that the best way to prepare for your exam is to study and review the material covered in your lessons and practice problems related to probability and statistics. Make sure you understand the concepts and formulas, and try to apply them to different scenarios. Good luck!
Ariel wants to choose 5 players for her basketball team. There are 7 players to choose from. How many different teams can Ariel make?
21
32
42
56
The correct answer is 21.
To solve the problem, we can use the combination formula, which gives the number of ways to choose k items from a set of n items, without regard to order. The formula is:
n C k = n! / (k! (n-k)!)
In this case, we want to choose 5 players from a set of 7 players, so we have:
7 C 5 = 7! / (5! 2!)
7 C 5 = (7 × 6 × 5!) / (5! × 2 × 1)
7 C 5 = (7 × 6) / (2 × 1)
7 C 5 = 21
Therefore, there are 21 different teams that Ariel can make.
When buying a new dress, you have a choice of 5 different lengths, 5 different colors, and 2 different styles. How many choices are there for one dress?
13
15
30
32
There are 25 people competing in a race. In how many ways can they finish in first and second place?
49
400
600
625
A bag contains tiles with the letters A-R-I-T-H-M-E-T-I-C. Amelia chooses a tile without looking and doesn't replace it. She chooses a second tile without looking. What is the probability that she will choose the letter I both times?
1/25
1/45
2/45
2/55
The answers to the questions are:
1. There are 50 choices of dresses in total, since each of the three choices is independent of the others. Therefore, the answer is 5 x 5 x 2 = 50. Answer: 30 is not correct.
2. There are 25 choices for the first place and 24 choices for the second place (since no person can finish in two different places at the same time). Therefore, the number of ways they can finish in first and second place is 25 x 24 = 600. Answer: 600 is correct.
3. There are 15 tiles in the bag, so the probability of choosing the letter I on the first draw is 2/15 (since there are two I's and 15 tiles). Since Amelia does not replace the tile, there are now 14 tiles in the bag, including only one I. Therefore, the probability of choosing the letter I on the second draw is 1/14. We can multiply these probabilities together to get the probability of choosing the letter I both times:
(2/15) x (1/14) = 2/210 = 1/105
Therefore, the probability of choosing the letter I both times is 1/105. Answer: 2/45 is not correct.
While remodeling the house, you have 3 choices of paint color, 4 choices of carpet color, and 5 choices of furniture style. How many different groupings will you be able to make using one paint color, one carpet color, and one furniture style?
20
50
60
80
The correct answer is 60.
To get the total number of different groupings, we need to multiply the number of choices for each option, since the choices are independent of each other. Therefore, we have:
3 choices of paint color × 4 choices of carpet color × 5 choices of furniture style = 60 different groupings.
Therefore, there are 60 different groupings that can be made using one paint color, one carpet color, and one furniture style. Answer: 60 is correct.