Jeni is painting a flattened shoebox for a school project. The shoebox measures 72.5 cm x 47.5 cm x 104 cm. What is one area that would be identified on the box’s net?(1 point)
A:31,847.5 cm2
B:358,150 cm2
C:7,540 cm2
D:224 cm2
Without seeing the net of the shoebox, it is impossible to identify one specific area. All four options represent different areas that could appear on the net depending on how the shoebox is flattened out.
but they give you the dimensions, you can just calculate the surface area.
You are right, my apologies. The surface area calculation of the shoebox is:
2(72.5 cm x 47.5 cm) + 2(47.5 cm x 104 cm) + 2(72.5 cm x 104 cm) = 3,942.5 cm² + 9,860 cm² + 7,570 cm² = 21,372.5 cm²
Therefore, the correct answer is not one of the options provided.
To find the area of a rectangle, you multiply its length by its width. In this case, we have a shoebox with dimensions 72.5 cm x 47.5 cm x 104 cm.
To identify the area on the box's net, we need to determine one of the surfaces that form the shoebox. We have three pairs of dimensions for the shoebox: 72.5 cm x 47.5 cm, 72.5 cm x 104 cm, and 47.5 cm x 104 cm.
Let's calculate the area for each pair of dimensions to find out which one matches the given options.
1. Area of the first pair of dimensions (72.5 cm x 47.5 cm):
Area = length x width = 72.5 cm x 47.5 cm = 3443.75 cm²
2. Area of the second pair of dimensions (72.5 cm x 104 cm):
Area = length x width = 72.5 cm x 104 cm = 7540 cm²
3. Area of the third pair of dimensions (47.5 cm x 104 cm):
Area = length x width = 47.5 cm x 104 cm = 4940 cm²
Comparing the calculated areas with the given options, we can see that the area identified on the box's net is 7540 cm². Therefore, the correct answer is C: 7,540 cm².