Calculate the wavelength of light emitted when each of the following transactions occur in the hydrogen atom.what type of electromagnetic radiation is emitted in each transion n=4-n=3
The energy of a photon emitted or absorbed during a transition in the hydrogen atom can be calculated using the Rydberg formula:
1/λ = R∞ (1/n₁² - 1/n₂²)
where λ is the wavelength of the photon, R∞ is the Rydberg constant (1.097x10^7 m^-1), and n₁ and n₂ are the initial and final energy levels of the electron, respectively.
For the transition n=4 to n=3, we have:
1/λ = R∞ (1/n₁² - 1/n₂²)
1/λ = (1.097x10^7 m^-1) (1/4² - 1/3²)
λ = 656.3 nm
This transition corresponds to the emission of a photon in the red part of the visible spectrum, specifically in the range of light known as "hydrogen-alpha" (Hα) emission.