A rectangular tank 0.30m × 0.30m × 0.60 m is filled with ethyl alcohol to a full depth of 0.30 the pressure at the surface of the alcohol is 1.013x10⁶ Pa. The force exerted at the bottom
To find the force exerted at the bottom of the tank, we need to calculate the weight of the ethyl alcohol in the tank. We can use the formula:
Weight = Density x Volume x Gravity
Where:
- Density of ethyl alcohol = 789 kg/m³
- Volume of tank = 0.30m x 0.30m x 0.60m = 0.054 m³
- Gravity = 9.81 m/s²
Substituting these values into the formula, we get:
Weight = 789 kg/m³ x 0.054 m³ x 9.81 m/s²
Weight = 416.07 N
This is the weight of the ethyl alcohol in the tank. To find the force exerted at the bottom of the tank, we need to convert this weight to pressure using the formula:
Pressure = Force / Area
The area of the bottom of the tank is:
Area = Length x Width
Area = 0.30m x 0.30m
Area = 0.09 m²
Substituting the values we have:
Pressure = 416.07 N / 0.09 m²
Pressure = 4,623 N/m²
So the force exerted at the bottom of the tank is 4,623 N.
Well, let's calculate the force exerted at the bottom of the tank, shall we? But first, let me put on my "thinker" hat...
Okay, so we have a rectangular tank, which means the area of the bottom will be the length multiplied by the width. In this case, it's 0.30m × 0.30m = 0.09 square meters.
Now, we need to find the weight of the ethyl alcohol column pressing down on the bottom of the tank. We can calculate that using the formula: Weight = Pressure × Area.
Weight = 1.013x10⁶ Pa × 0.09 m²
*doing some quick math*
Weight = 91,170 Newtons
So, the force exerted at the bottom of the tank is approximately 91,170 Newtons. That's quite a hefty force, but luckily the tank can handle it!
Remember, my calculations are as accurate as my sense of humor, so take them with a pinch of clown powder!
To find the force exerted at the bottom of the tank, we can use the concept of pressure.
Pressure is defined as the force per unit area. Therefore, we can find the force by multiplying the pressure by the area exerted.
Given that the tank is rectangular and has dimensions of 0.30m × 0.30m, we can find the area by multiplying these dimensions together:
Area = 0.30m × 0.30m
Area = 0.09 square meters
The pressure given is 1.013x10⁶ Pa.
Now we can calculate the force using the formula:
Force = Pressure × Area
Substituting the values:
Force = 1.013x10⁶ Pa × 0.09 square meters
Calculating the value:
Force = 91,170 newtons
Therefore, the force exerted at the bottom of the tank is 91,170 newtons.
To find the force exerted at the bottom of the tank, we need to consider the pressure exerted by the ethyl alcohol.
The pressure exerted by a fluid at a particular depth is given by the equation:
Pressure = Density × Acceleration due to gravity × Depth
First, let's calculate the density of ethyl alcohol. The density of ethyl alcohol is approximately 789 kg/m³.
Next, we need to determine the depth of the ethyl alcohol in the tank. Since the tank is filled to a depth of 0.30 m, the depth is equal to 0.30 m.
Lastly, the acceleration due to gravity can be taken as 9.8 m/s².
Using the formula, we can find the pressure exerted by the ethyl alcohol at the bottom of the tank:
Pressure = (Density × Acceleration due to gravity × Depth)
= (789 kg/m³ × 9.8 m/s² × 0.30 m)
= 2308.38 Pa
Therefore, the force exerted at the bottom of the tank is 2308.38 Pa.