A coin is flipped and a spinner is spun simultaneously. The spinner is divided into six equally sized sections labeled with 1, 2, 3, 4, 5, 6. What is the probability of flipping a tail and landing on 5?
The probability of flipping a tail is 1/2 and the probability of landing on 5 on the spinner is 1/6. Since the events are happening simultaneously, we can use the Multiplication Rule of Probability, which states that the probability of two independent events happening together is the product of their individual probabilities. Therefore, the probability of flipping a tail and landing on 5 is:
1/2 x 1/6 = 1/12
So the probability of flipping a tail and landing on 5 is 1/12 or approximately 0.083.
If two events are independent, the probability of both events occurring is the product of their individual probability. Events A and B are independent with P(A)=0.3 and P(B)=0.25. What is the probability of events A and B happening at the same time? Write your answer in decimal form.
Since events A and B are independent, the probability of both occurring is the product of their individual probabilities:
P(A and B) = P(A) x P(B) = 0.3 x 0.25 = 0.075
Therefore, the probability of events A and B happening at the same time is 0.075 or 7.5%.
Use the table to answer the question.
Studying Online
Girls Boys Row total
Want the option to keep studying online 10 3 13
Don’t want the option to keep studying online 5 7 12
Column total 15 10 25What is the probability of selecting a student who wants the option to keep studying online? Write your answer in percent form.
The total number of students who want the option to keep studying online is 13, out of a total of 25 students. Therefore, the probability of selecting a student who wants the option to keep studying online is:
13/25 = 0.52
Multiplying by 100% to convert to percent form gives:
0.52 x 100% = 52%
Therefore, the probability of selecting a student who wants the option to keep studying online is 52%.
A money envelope contains five $10 bills, ten $20 bills, and fifteen $50 bills. Sandra randomly selects two bills without returning the first bill. What is the probability of getting a $10 bill then a $50 bill? Write your answer in the simplest form of fraction
The probability of getting a $10 bill on the first draw is 5/30 (since there are 5 $10 bills out of 30 total bills). After this bill is not returned, there are 29 bills left in the envelope, of which 15 are $50 bills. Therefore, the probability of getting a $50 bill on the second draw, given that a $10 bill was drawn first and not returned, is 15/29.
Since we need both events to happen (getting a $10 bill then a $50 bill), we can use the multiplication rule and multiply the probabilities of the two events:
P($10, then $50) = (5/30) x (15/29)
Simplifying this fraction by canceling out common factors gives:
P($10, then $50) = (1/6) x (15/29) = 5/58
Therefore, the probability of getting a $10 bill then a $50 bill is 5/58 in the simplest form of fraction.
H - shaded
O - not shaded
N - not shaded
E - shaded
S - shaded
T - not shaded
A spinner labeled with the letters of the word HONEST is to be spun once. Describe the probability of landing on an unshaded section in the sample space.
A: 1/6
B: 3
C: 1/3
D:1/2
There are three unshaded sections on the spinner, labeled O, N, and T. Since there are a total of six sections on the spinner, each labeled with one of the letters in the word HONEST, the probability of landing on an unshaded section is the number of unshaded sections (3) divided by the total number of sections (6):
P(unshaded) = 3/6 = 1/2
Therefore, the probability of landing on an unshaded section in the sample space is 1/2.
So the answer is D: 1/2.
Which set of events is dependent?(1 point)
Responses
rolling a number cube and flipping a coin
rolling a number cube and flipping a coin
choosing a marble from a box, replacing it, then choosing another marble
choosing a marble from a box, replacing it, then choosing another marble
the event of getting two heads when flipping two fair coins
, the event of getting two heads when flipping two fair coins
choosing a ball from a bag and then choosing another ball without replacing the first