THE TABLE summarizes the results of spinning the spinner shown red 6 blue 5 green 3 yellow 4 what is the experimental probability of the spinner landing on red
Based on the given information, there are a total of 18 outcomes (6 + 5 + 3 + 4) when the spinner is spun. The spinner landing on red occurred 6 times out of these 18 outcomes. Therefore, the experimental probability of the spinner landing on red is:
6/18 or simplified, 1/3 or approximately 0.33 or 33.3%
THE TABLE summarizes the results of spinning the spinner shown
red 6 blue 5 green 3 yellow 4
what is the theoretical probability of the spinner landing on red
The theoretical probability of the spinner landing on red can be calculated by dividing the number of red sectors by the total number of sectors on the spinner. In this case, there are 6 red sectors out of a total of 18 sectors on the spinner.
Therefore, the theoretical probability of the spinner landing on red is:
6/18 or simplified, 1/3 or approximately 0.33 or 33.3%
The table summarizes the results of spinning the spinner shown.2. What is the theoretical probability of the spinner landing on red? (1 point)
A 1/2
B 1/3
C1/4
There is no table given in the question. Please provide the necessary information to answer the question.
Color: Red Blue Green Yellow
Number
Of times
Spun: 6 5 3 4
The table summarizes the results of spinning the spinner shown.2. What is the theoretical probability of the spinner landing on red? (1 point)
A 1/2
B 1/3
C1/4
Color: Red Blue Green Yellow
Number
Of times
Spun: 6 5 3 4
The spinner has a total of 4 colors (red, blue, green, and yellow) and the table shows that the spinner landed on red 6 times out of 18 spins.
The theoretical probability of the spinner landing on red can be calculated as follows:
Theoretical probability of landing on red = (Number of red sectors) / (Total number of sectors)
There are 6 red sectors out of a total of 18 sectors on the spinner so:
Theoretical probability of landing on red = 6 / 18
Simplifying this fraction gives:
Theoretical probability of landing on red = 1 / 3
Therefore, the answer is B, 1/3.
Two coins were tossed 10 times. The results are shown in the table below.
Toss: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10
Result:HH, TT, HT, TH, HT, HH, TT, TH, HT
3. What is the experimental probability that at least one of the coins landed on heads? Express the probability as a decimal.
A00.8
B00.2
C00.6
Out of the 10 tosses, we can see that in each toss either both coins land heads (HH) or both coins land tails (TT) or one coin lands heads and the other lands tails (HT or TH). So if both coins land tails in a toss, it means that neither of the coins landed heads. Therefore if we count the number of tosses where we did not get any heads, that would give us the number of tosses where there were no heads on either coin.
From the table provided we see that there are only 2 tosses where we did not get any heads (tosses 2 and 7), and the other 8 tosses have at least one head.
Therefore, the experimental probability that at least one of the coins landed on heads is:
Number of tosses with at least one head / Total number of tosses
8 / 10 = 0.8
Hence, the answer is A) 0.8.