7.

The local deli sells cheese wheels. Each cheese wheel is a cylinder. The height of the cheese wheel is 2.8 inches and the volume of the cheese wheel is 155.1 cubic inches. What is the radius of the cheese wheel? Use 3.14 for π.
The answer is rounded to the nearest tenth.

8.8


8.8in

17.6


17.6in

4.2


4.2in

1
,
363.6


1,363.6in

The radius of the cheese wheel is 3.5 inches.

To find the radius, we can use the formula for the volume of a cylinder:

V = πr^2h

Plugging in the given values, we get:

155.1 = 3.14 x r^2 x 2.8

Rearranging and solving for r, we get:

r^2 = 155.1 / (3.14 x 2.8)

r^2 ≈ 14.81

r ≈ √14.81

r ≈ 3.5

Therefore, the radius of the cheese wheel is approximately 3.5 inches.

To find the radius of the cheese wheel, we can use the formula for the volume of a cylinder:

V = πr^2h

Given that the height of the cheese wheel is 2.8 inches and the volume is 155.1 cubic inches, we can substitute these values into the formula to solve for the radius.

155.1 = 3.14 * r^2 * 2.8

Dividing both sides of the equation by 3.14 * 2.8:

155.1 / (3.14 * 2.8) = r^2

Simplifying the right-hand side:

155.1 / 8.792 = r^2

Taking the square root of both sides:

√(155.1 / 8.792) = r

Calculating the square root:

r ≈ 4.2

Therefore, the radius of the cheese wheel is approximately 4.2 inches.

To find the radius of the cheese wheel, we can use the formula for the volume of a cylinder, which is V = πr^2h, where V represents the volume, r represents the radius, and h represents the height.

Given that the height of the cheese wheel is 2.8 inches and the volume of the cheese wheel is 155.1 cubic inches, we can substitute these values into the formula:

155.1 = 3.14 * r^2 * 2.8

First, divide both sides of the equation by 2.8:

55.4 = 3.14 * r^2

Then, divide both sides of the equation by 3.14:

r^2 = 17.6

To solve for r, take the square root of both sides of the equation:

r = √17.6

The answer is rounded to the nearest tenth, so r ≈ 4.2 inches.

Therefore, the radius of the cheese wheel is approximately 4.2 inches.