Simplified the expression
-x(6x-7)
-6x²+7x
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Find the area of the rectangle with a length of 32 inches and a width of 20 inches. (1 point)
52 in.
2
6,400 in.
2
520 in.
2
640 in.
The area of a rectangle is given by length times width. Therefore, the area of the given rectangle is:
Area = length x width = 32 x 20 = 640 square inches.
So the answer is 640 in. 2
John wants to build a fence around his pool. The pool is 22 feet long by 23 feet wide. The fence is to be 15
feet from the edge of the pool.
a. What are the outside dimensions of the area surrounding the pool?
b. How many feet of fencing will John need?
(1 point)
37 ft by 38 ft; 75 ft
37 ft by 38 ft; 150 ft
52 ft by 53 ft; 105 ft
52 ft by 53 ft; 210
a. To find the outside dimensions of the area surrounding the pool, we need to add 15 feet to each side of the pool.
Length with the fence = 22 + 2(15) = 52 feet
Width with the fence = 23 + 2(15) = 53 feet
Therefore, the outside dimensions of the area surrounding the pool are 52 feet by 53 feet.
b. To calculate the amount of fencing needed, we need to find the perimeter of the area surrounding the pool.
Perimeter = 2(length + width)
Perimeter = 2(52 + 53)
Perimeter = 2(105)
Perimeter = 210 feet
Therefore, John will need 210 feet of fencing.
So the answer is 52 ft by 53 ft; 210.
Find the area of the triangle.
26 by 82
Not drawn to scale.
(1 point)
108 ft
1,066 ft
266 ft
533 ft
To find the area of a triangle, we use the formula:
Area = 1/2 x base x height
In this case, the base is the length of 82 and the height is the length of 26.
Area = 1/2 x 82 x 26
Area = 1,066 square feet
Therefore, the area of the given triangle is 1,066 ft.
Find the area of the parallelogram with a base of 276.5 cm and a height of 20.3 cm. (1 point)
5,612.95 cm2
11,225.9 cm2
22,451.8 cm2
3,741.96 cm2