suppose you spin the spinner once. find the probability. P(yellow) (1 point) 1/8 1/6 1/4 1/2
Without knowing the specifics of the spinner, we cannot determine the exact probability.
suppose you spin the spinner once. find the probability. P(yellow) (1 point) 1/8 1/6 1/4 1/2
the spinner has an arrow with the point on R and the end on B
If the spinner has two colors, R (red) and B (blue), and the arrow points to R and B equally, then the probability of getting yellow (assuming it exists as an option) would be 0, since it is not one of the options on the spinner.
In this case, we cannot determine the probability of getting yellow with the given information.
Suppose you spin the spinner once. Find the probability.
there is 4 R 2 B 1 G and 1 Y, the point of the spinner is on R and the end is on B
There are a total of 4 + 2 + 1 + 1 = 8 equally likely outcomes on the spinner. The probability of getting yellow is 1 out of 8 since there is only one yellow section on the spinner.
Therefore, the probability of getting yellow is:
P(Yellow) = 1/8
suppose you spin the spinner once. find the probability. 4 R 2 B 1 G 1 Y
P(red or blue)
There are a total of 4 + 2 = 6 equally likely outcomes on the spinner that are either red or blue.
Therefore, the probability of getting red or blue is:
P(Red or Blue) = 6/8 = 3/4
Note: We use 6 as the numerator since there are 4 red sections and 2 blue sections on the spinner.
Drink survey. Drink A, B, C, D, E number of shoppers who preferred it 10, 15, 7, 3, 6
what is the probability that 1 shopper, selected at random preferred neither drink E nor Drink C?
We need to start by finding the total number of shoppers who preferred drink E or drink C.
Number of shoppers who preferred E or C = 7 + 6 = 13
Now, we need to subtract this number from the total number of shoppers to find the number of shoppers who preferred neither E nor C.
Total number of shoppers = 10 + 15 + 7 + 3 + 6 = 41
Number of shoppers who did not prefer E or C = Total number of shoppers - Number of shoppers who preferred E or C = 41 - 13 = 28
Therefore, the probability that 1 shopper, selected at random preferred neither drink E nor drink C is:
P(Neither E nor C) = Number of shoppers who did not prefer E or C / Total number of shoppers
P(Neither E nor C) = 28/41
P(Neither E nor C) ≈ 0.683 or around 68.3% (rounded to three decimal places)