A survey asked 30 tenants in an apartment building how many TV sets they had in their apartment . Let the random variable denote the number of televisions per apartment . The survey results are recorded in the following table : X 0 1 23 4 or more Frequency 1 6 147 2 If one tenant is selected at random , what the probability that they have fewer than 3 television sets in their apartment ? Round your answer to the hundredths place .
The probability that a tenant has fewer than 3 television sets in their apartment is the sum of the frequencies for X = 0, 1, and 2, divided by the total number of tenants surveyed:
P(X < 3) = (1 + 6 + 14)/30 = 21/30 = 0.70
Rounded to the hundredths place, the probability is 0.70.