A 12-V battery is connected to a light bulb with a resistance of 2Ω. What is the current in the circuit? **You must show all your work to receive credit. Your answer must include the correct unit.**

We can use Ohm's Law to solve this problem:

Ohm's Law: V = IR
where V is the voltage, I is the current, and R is the resistance.

We are given the voltage (V = 12V) and the resistance (R = 2Ω), so we can solve for the current (I).

I = V/R
I = 12V/2Ω
I = 6 amps

Therefore, the current in the circuit is 6 amps (A).