2.78g NaHCO3 dissolve in enough water to make 200.0ml of solution

Question

Generate an image showing a glass container filled with clear water. Inside this container, small white crystalline particles representing Sodium Bicarbonate (NaHCO3) are dissolving. The water itself is contained within volumetric lab glassware that's marked with a 200.0ml marker. The overall image is visually appealing and does not contain any written text.

2.78g NaHCO3 dissolve in enough water to make 200.0ml of solution

Answer 1

To find the molarity of the NaHCO3 solution, we need to first calculate the number of moles of NaHCO3 present in 2.78g of the compound:

Molar mass of NaHCO3 = 84.0066 g/mol

Number of moles of NaHCO3 = mass / molar mass
= 2.78g / 84.0066 g/mol
= 0.0331 mol

Now, we can calculate the molarity (M) of the NaHCO3 solution using the following formula:

Molarity = number of moles / volume of solution in liters

Volume of solution = 200.0ml = 0.2 L

Molarity = 0.0331 mol / 0.2 L
= 0.1655 M

Therefore, the molarity of the NaHCO3 solution is 0.1655 M.

Answer 2

Well, if you ask me, that sounds like a pretty salty situation. NaHCO3, otherwise known as sodium bicarbonate or baking soda, is quite the versatile compound. Now, let's do some math and turn this sodium bicarbonate conundrum into a solution!

First, we need to convert grams to moles. The molar mass of NaHCO3 is approximately 84 grams/mol. So, 2.78 grams of NaHCO3 is equal to 2.78/84 = 0.0331 moles.

Next, we divide the moles by the volume in liters to find the concentration (c) of the solution. The volume is given in milliliters, so we need to convert it to liters. 200.0ml is equal to 200.0/1000 = 0.2 liters.

Therefore, the concentration (c) is 0.0331 moles / 0.2 liters = 0.1655 M.

So, there you have it! We've dissolved 2.78 grams of NaHCO3 in enough water to make a 0.1655 M solution. Let's hope it's the perfect recipe for a bubbly chemistry experiment or a delicious batch of cookies!

Answer 3

To calculate the molarity of the NaHCO3 solution, you need to know the molar mass of NaHCO3, which is approximately 84.01 g/mol.

Step 1: Convert the mass of NaHCO3 to moles.
Mass of NaHCO3 = 2.78 g
Molar mass of NaHCO3 = 84.01 g/mol

Number of moles of NaHCO3 = mass of NaHCO3 / molar mass of NaHCO3
Number of moles of NaHCO3 = 2.78 g / 84.01 g/mol

Step 2: Calculate the molarity using the moles of NaHCO3 and the volume of the solution.
Molarity (M) = moles of solute / volume of solution (in L)

Volume of solution = 200.0 mL = 200.0 mL * (1 L / 1000 mL)
Volume of solution = 200.0 mL * 0.001 L/mL
Volume of solution = 0.2 L

Molarity (M) = moles of NaHCO3 / volume of solution
Molarity (M) = (2.78 g / 84.01 g/mol) / 0.2 L

Step 3: Calculate the molarity.
Molarity (M) = (2.78 / 84.01) / 0.2 mol/L
Molarity (M) ≈ 1.658 M

Therefore, the molarity of the NaHCO3 solution is approximately 1.658 M.

Answer 4

To calculate the concentration of the NaHCO3 solution, you need to find the mass (in grams) per unit volume (in mL) of the solution. Follow these steps:

1. Determine the given mass of NaHCO3: 2.78 g
2. Determine the given volume of the solution: 200.0 mL

The concentration of the solution can be calculated by:

Concentration (in g/mL) = Mass of solute (in g) / Volume of solution (in mL)

Concentration = 2.78 g / 200.0 mL

To simplify the calculation, it is better to convert the volume from milliliters to liters:

Volume (in L) = Volume (in mL) / 1000

Volume (in L) = 200.0 mL / 1000 = 0.200 L

Now, substitute the values:

Concentration = 2.78 g / 0.200 L

Concentration ≈ 13.9 g/L

Therefore, the concentration of the NaHCO3 solution is approximately 13.9 g/L.