How much more kinetic energy does a 6-kilogram bowling ball have when it is rolling at 16 mph (7.1 meters per second) than when it is rolling at 14 mph (6.2 meters per second)?
A). 35.9 J
B). 151.2 J
C). 1.3 J
D). 266.5 J
The kinetic energy of an object is given by the formula KE = 1/2 mv^2, where m is the mass of the object and v is its velocity.
First, let's calculate the kinetic energy of the bowling ball when it is rolling at 16 mph (7.1 m/s):
KE1 = 1/2 (6 kg) (7.1 m/s)^2 = 151.98 J
Now, let's calculate the kinetic energy of the same bowling ball when it is rolling at 14 mph (6.2 m/s):
KE2 = 1/2 (6 kg) (6.2 m/s)^2 = 113.52 J
The difference in kinetic energy between the two speeds is simply the change between KE1 and KE2:
KE1 - KE2 = 151.98 J - 113.52 J = 38.46 J
Therefore, the answer is A) 35.9 J (rounded to one decimal place).