2. (Image: Start Layout enlarged left brace 1st row 10x plus 3y equals negative 11 2nd row 8x plus 2y equals negative 6 end layout) (1 point)
(Image: left-parenthesis negative 2 comma 3 right-parenthesis)
(Image: left-parenthesis negative 1 comma 1 right-parenthesis)
(Image: left-parenthesis 1 comma negative 7 right-parenthesis)
no solution
maybe if you learned to type math, we could get somewhere. How about
10x+3y = -11
8x+2y = -6
A little Gaussian elimination proceeds as follows:
20x+6y = -22
24x+6y = -18
now subtract to get
4x = 4
x = 1
that means y = -7
looks like C to me
Thank you for typing the equations in a format that is easier to read and solve. I apologize for the inconvenience caused earlier due to my inability to type math symbols. Yes, you are correct. The solution to the system of equations is (1,-7), which corresponds to option C.
pls help
Please let me know what you need help with, and I'll do my best to assist you.
thank you and sorry
No need to apologize. Let me know if you need any assistance.
To determine if there is a solution to the system of equations represented by the given layout, we can use a method called substitution.
1. Start with the first equation: 10x + 3y = -11.
2. Substitute the values from the first set of parentheses into the equation:
Replace x with -2 and y with 3. So, 10(-2) + 3(3) = -11.
Simplifying, we get -20 + 9 = -11.
-11 = -11, which is true.
3. Now, let's substitute the values from the second set of parentheses into the second equation:
Replace x with -1 and y with 1. So, 8(-1) + 2(1) = -6.
Simplifying, we get -8 + 2 = -6.
-6 = -6, which is true.
Since both equations are true when substituting the respective values, we can conclude that the given set of parentheses (-2, 3) and (-1, 1) satisfies the system of equations.
However, there is a third set of parentheses given, (1, -7). To verify if it satisfies the system, we can follow the same substitution process:
4. Substitute the values from the third set of parentheses into the first equation:
Replace x with 1 and y with -7. So, 10(1) + 3(-7) = -11.
Simplifying, we get 10 - 21 = -11.
-11 = -11, which is true.
5. Substitute the values from the third set of parentheses into the second equation:
Replace x with 1 and y with -7. So, 8(1) + 2(-7) = -6.
Simplifying, we get 8 - 14 = -6.
-6 = -6, which is true.
Since both equations are also true when substituting (1, -7), we can say that the third set of parentheses is also a solution.
Therefore, the system of equations has multiple solution sets, represented by the parentheses (-2, 3), (-1, 1), and (1, -7).