How much heat is lost when 4110 Fran metal bar whose specific heat is 0.2311j/ gc cools from 100c to 20c
First, we need to calculate the change in temperature:
ΔT = final temperature - initial temperature = 20°C - 100°C = -80°C
Note that the change in temperature is negative, indicating a cooling process.
Next, we can calculate the amount of heat lost using the formula:
Q = mcΔT
Where:
- Q is the amount of heat lost (in joules)
- m is the mass of the metal bar (in grams)
- c is the specific heat of the metal (in J/g°C)
- ΔT is the change in temperature (in °C)
Substituting the given values:
Q = (4110 g) x (0.2311 J/g°C) x (-80°C)
Q = -76,234.04 J
Note that the negative sign indicates that heat is lost (rather than gained). Therefore, the answer is 76,234.04 J of heat lost when the Fran metal bar cools from 100°C to 20°C.
How much heat is required to raise the temperature of 854 g of water from 23.5 c to 85 c
We can use the formula:
Q = mcΔT
Where:
- Q is the amount of heat needed (in joules)
- m is the mass of the water (in grams)
- c is the specific heat of water (4.184 J/g°C)
- ΔT is the change in temperature (in °C)
Substituting the given values:
Q = (854 g) x (4.184 J/g°C) x (85°C - 23.5°C)
Q = 251,704.72 J
Therefore, 251,704.72 J of heat is required to raise the temperature of 854 g of water from 23.5°C to 85°C.
To calculate the amount of heat lost by a metal bar as it cools, you can use the formula:
Q = mcΔT
Where:
Q is the amount of heat lost (in joules)
m is the mass of the metal bar (in grams)
c is the specific heat capacity of the metal (in joules per gram per degree Celsius)
ΔT is the change in temperature (in degrees Celsius)
In this case, you know the specific heat capacity (c) of the metal bar is 0.2311 J/g°C. The change in temperature (ΔT) is from 100°C to 20°C, so ΔT = 100°C - 20°C = 80°C.
However, you didn't provide the mass (m) of the metal bar, so I'm unable to provide a specific answer. To calculate the heat lost, you need to know the mass of the metal bar in grams. Once you have the mass, you can substitute it into the formula along with the other values and calculate the answer.