Fifty students in a class took an examination in French and mathematics,if14 of them passed French only, 23 passed in both French and mathematics and 5 of failed in both subjects,fine
1.the number of students who passed in French
2.the probability of selecting a student who passed in mathematics
1. To find the number of students who passed in French, we need to add the number of students who passed French only to the number of students who passed both French and mathematics:
Number of students who passed in French = 14 + 23 = 37
Therefore, 37 students passed in French.
2. To find the probability of selecting a student who passed in mathematics, we need to divide the number of students who passed in mathematics (including those who passed both French and mathematics) by the total number of students in the class:
Number of students who passed in mathematics = 23 + 5 = 28
Total number of students in the class = 50
Probability of selecting a student who passed in mathematics = 28/50 = 0.56 or 56%
Therefore, the probability of selecting a student who passed in mathematics is 0.56 or 56%.
1. Well, clearly we wouldn't want any "passing french fries" in our class, right? Anyway, let's get serious. To find the number of students who passed in French, we can add the number of students who passed French only with the number of students who passed in both subjects. So, that would be 14 + 23 = 37 students.
2. Ah, the probability of selecting a student who passed in mathematics. Let's see here. Since there were 23 students who passed in both subjects, that means they passed in mathematics as well. And since 5 students failed both subjects, we need to subtract them from the total number of students. So, that would be: (23 - 5) / 50 = 18/50, which simplifies to 9/25. So, the probability is 9/25.
Hope that brought a smile to your face while providing you the answers you were looking for!
To find the number of students who passed in French, we need to consider the students who passed French only and those who passed both French and Mathematics.
1. Number of students who passed in French = number of students who passed French only + number of students who passed both French and Mathematics
Given:
Number of students who passed French only = 14
Number of students who passed both French and Mathematics = 23
Number of students who passed in French = 14 + 23 = 37
Therefore, the number of students who passed in French is 37.
2. To find the probability of selecting a student who passed in mathematics, we need to consider the number of students who passed in mathematics and divide it by the total number of students.
Probability of selecting a student who passed in mathematics = Number of students who passed in mathematics / Total number of students
Given:
Number of students who passed both French and Mathematics = 23
Total number of students = 50
Probability of selecting a student who passed in mathematics = 23 / 50 = 0.46 or 46%
Therefore, the probability of selecting a student who passed in mathematics is 46%.
To find the number of students who passed in French:
1. Start with the total number of students who took the examination, which is given as 50.
2. Subtract the number of students who failed in both subjects from the total, which is given as 5.
3. Subtract the number of students who passed in both French and mathematics from the result obtained in step 2, which is given as 23.
4. The remaining value will be the number of students who passed in French only.
Therefore, to calculate the number of students who passed in French:
50 - 5 - 23 = 22
So, 22 students passed in French.
To find the probability of selecting a student who passed in mathematics:
1. Add the number of students who passed in both French and mathematics to the number of students who passed in mathematics only, which is given as 23.
2. Divide the result obtained in step 1 by the total number of students who took the examination, which is given as 50.
Therefore, to calculate the probability:
23 / 50 = 0.46 or 46%
So, the probability of selecting a student who passed in mathematics is 0.46 or 46%.