Calculate the PH of 0.01M tetraoxosulphate vi acid solution
To calculate the pH of a 0.01 M tetraoxosulfate(VI) acid solution, we need to know the dissociation constant of the acid and what it dissociates into when dissolved in water.
Tetraoxosulfate(VI) acid is also known as sulfuric acid, with the chemical formula H2SO4. It is a strong acid, which means it dissociates completely in water into H+ and SO4(2-) ions.
H2SO4 -> 2H+ + SO4(2-)
The concentration of H+ ions released by 0.01 M H2SO4 will be:
[H+] = 2 * [H2SO4] = 2 * 0.01 M = 0.02 M
Now, to calculate the pH, we can use the formula:
pH = -log10([H+])
pH = -log10(0.02)
pH ≈ 1.7
So, the pH of a 0.01 M tetraoxosulfate(VI) acid solution is approximately 1.7.