a boy mistakenly measured the side of a square of side 4m as 3m.what is the percentage error in his calculated area.a)56.3% b)43.8% c)17.9% d)14.1% e)36%
The correct side length of the square is 4m, but the boy measured it as 3m.
Percentage error in side length = [(4-3)/4] x 100% = 25%
The area of the square is given by A = side x side. Therefore, the correct area is 4m x 4m = 16m^2.
The boy calculated the area as 3m x 3m = 9m^2.
Percentage error in area = [(16-9)/16] x 100% = 43.8%
Therefore, the answer is (b) 43.8%.