2.54 of sodium chloride were dissolved in water and the solution made up to 100cm^3. What is the solution in moldm^-3
To determine the solution in moldm^-3, we need to know the number of moles of sodium chloride in the solution.
Number of moles = mass ÷ molar mass
Molar mass of sodium chloride (NaCl) = 22.99 + 35.45 = 58.44 g/mol
Number of moles of NaCl = 2.54 g ÷ 58.44 g/mol = 0.0434 mol
Now we can find the concentration in moldm^-3:
Concentration = number of moles ÷ volume in dm^3
Volume in cm^3 = 100 cm^3 = 0.1 dm^3
Concentration = 0.0434 mol ÷ 0.1 dm^3 = 0.434 moldm^-3
Therefore, the concentration of the sodium chloride solution is 0.434 moldm^-3.
To find the concentration of the solution in moldm^-3, we need to determine the number of moles of sodium chloride that are present in the solution first.
The given information is that 2.54 grams of sodium chloride were dissolved. To calculate the number of moles, we can use the molar mass of sodium chloride, which is 58.44 g/mol.
First, convert the mass of sodium chloride to moles:
moles of sodium chloride = mass of sodium chloride / molar mass
moles of sodium chloride = 2.54 g / 58.44 g/mol ≈ 0.0435 mol
Now, we need to determine the volume of the solution in dm^3. The given volume is 100 cm^3, which is equivalent to 100/1000 = 0.1 dm^3.
Next, calculate the concentration of the solution in moldm^-3:
concentration (moldm^-3) = moles / volume (dm^3)
concentration = 0.0435 mol / 0.1 dm^3
concentration ≈ 0.435 moldm^-3
Therefore, the solution has a concentration of approximately 0.435 moldm^-3.
To determine the solution concentration in mol dm^-3, we need to know the molar mass of sodium chloride and the number of moles of sodium chloride dissolved in the solution.
The molar mass of sodium chloride (NaCl) is approximately 58.44 g/mol, which is the sum of the atomic masses of sodium (22.99 g/mol) and chlorine (35.45 g/mol).
To find the number of moles of sodium chloride in the solution, we use the equation:
Moles = Mass / Molar mass
Given that 2.54 g of sodium chloride was dissolved in water, we have:
Moles = 2.54 g / 58.44 g/mol ≈ 0.0435 mol
Now that we know the number of moles of sodium chloride, we can calculate the concentration of the solution.
Concentration (in mol dm^-3) = Moles / Volume (in dm^3)
The volume of the solution is given as 100 cm^3, which is equivalent to 0.1 dm^3.
Concentration = 0.0435 mol / 0.1 dm^3
Concentration ≈ 0.435 mol dm^-3
Therefore, the concentration of the sodium chloride solution is approximately 0.435 mol dm^-3.