What is the energy of a mole of radio wave photons with a frequency of 909kHz?
The energy of a photon can be calculated using the formula E = hν, where E is the energy of the photon, h is Planck's constant (6.626 x 10^-34 J s), and ν is the frequency of the photon.
Thus, the energy of a single radio wave photon with a frequency of 909 kHz can be calculated as:
E = (6.626 x 10^-34 J s)(909,000 Hz)
E = 6.03 x 10^-26 J
To determine the energy of a mole of photons, we can use Avogadro's constant (6.022 x 10^23 photons/mol). Thus, the energy of a mole of radio wave photons with a frequency of 909 kHz is:
E = (6.03 x 10^-26 J/photon)(6.022 x 10^23 photons/mol)
E = 3.63 x 10^-2 J/mol
Therefore, the energy of a mole of radio wave photons with a frequency of 909 kHz is approximately 3.63 x 10^-2 J/mol.