Assume that a procedure yields a binomial distribution with n=3 trials and a probability of success of p=0.60. Use a binomial probability table to find the probability that the number of successes x is exactly 1
Using a binomial probability table, the probability of getting exactly one success with n=3 trials and a probability of success of p=0.60 can be found as follows:
P(x=1) = 3C1 * (0.60)^1 * (1-0.60)^2
where 3C1 is the number of ways to choose one success from three trials, which is 3.
P(x=1) = 3 * 0.60 * 0.40^2
P(x=1) = 0.432
Therefore, the probability of getting exactly one success is 0.432.