How many Grams of NaoH are needed to netutralize 50 gram of H2so4
To neutralize H2SO4 with NaOH, we need to use the balanced chemical equation:
H2SO4 + 2NaOH → Na2SO4 + 2H2O
From this equation, we see that 1 mole of H2SO4 reacts with 2 moles of NaOH.
First, we need to determine the number of moles of H2SO4 in 50 grams.
The molar mass of H2SO4 is:
(2 x H) + (1 x S) + (4 x O) = (2 x 1.008) + (32.07) + (4 x 16.00) = 98.08 g/mol
Now we can find the number of moles of H2SO4 in 50 grams:
moles H2SO4 = mass H2SO4 / molar mass H2SO4 = 50 g / 98.08 g/mol = 0.5097 mol
Since 1 mole of H2SO4 reacts with 2 moles of NaOH, we need twice the number of moles of NaOH:
moles NaOH = 0.5097 mol H2SO4 * 2 = 1.0194 mol NaOH
Now we can find the mass of NaOH needed to neutralize H2SO4. The molar mass of NaOH is:
(1 x Na) + (1 x O) + (1 x H) = (22.99) + (16.00) + (1.008) = 40.00 g/mol
Mass NaOH = moles NaOH * molar mass NaOH = 1.0194 mol * 40.00 g/mol = 40.78 grams
So, we need 40.78 grams of NaOH to neutralize 50 grams of H2SO4.